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4 years ago

HELP ME WITH THESE TWO PLEASE PLEASE ILL GIVE BRAINLIEST

Mathematics

2 answers:

faltersainse [42]4 years ago

6 0

Answer:

1. C. 28/54

2. A. 5/22

Step-by-step explanation:

1. Simplify each fraction to see which of the four are equal to 4/9.

2. Convert each to a decimal to see which is between 2/11 and 3/11.

LiRa [457]4 years ago

4 0

Answer: 1. The fraction 28 over 54 is NOT equivalent to 4 over 9. For number two the answer would be C) 5 over 11 would be in between 2 over 11 and 3 over 11. Hope this helps. (:

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Rose works eight hours a day for five days a week. how many hours will she work in six weeks

MAVERICK [17]

8 hrs a day for 5 days a week = (8 * 5) = 40 hrs per week
in 6 weeks.....40 * 6 = 240 hrs <==

6 0

3 years ago

How to solve 0.01x+0.07y=0.22 and 0.03x-0.05y=0.14 by substitution

kap26 [50]

0.01x + 0.07y = 0.22
0.03x -0.05y = 0.14

x + 7y = 22
3x - 5y = 14

x = 22 -7y

3*(22-7y) -5y =14
66 - 21y -5y =14
-26y = - 52
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5 0

3 years ago

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Marizza181 [45]

Answer

test statistic $t = -2.27$

P-value $p- value = 0.0198$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 5$

The first sample mean is $\= x_1 = 1.76 \ mm$

The first standard is $s_1 = 0.55$

The second is $sample \ size\ is\ n_2 = 11$

The second sample mean is $\= x_2 = 2.56$

The second standard deviation is $\sigma = 0.84$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

The alternative hypothesis is $H_a: \mu_1 - \mu_2 < 0$

Generally the test statistics is mathematically represented as

$t = \frac{ (\= x _1 - \= x_2) - ( \mu_1 - \mu_2)}{ \sqrt{\frac{s_1 ^2 }{ n_1 } + \frac{s_1 ^2 }{ n_1 } } }$

=> $t = \frac{ (1.76 - 2.56 ) - 0 }{ \sqrt{\frac{0.55^2 }{ 5 } + \frac{0.84^2 }{11 } } }$

=> $t = -2.27$

Generally degree of freedom is mathematically represented as

$df = n_1 + n_2 - 2$

=> $df = 5 + 11 - 2$

=> $df = 14$

From the student t distribution table the probability value to the left that corresponds to $t = -2.27$ at a degree of freedom of $df = 14$ is

$p- value = 0.0198$

6 0

3 years ago

Solution of 4 |2y-3| -1 =11 step by step

joja [24]

Answer:

y = 0, 3

Step-by-step explanation:

1) Add 1 to both sides.

4 ∣ 2y −3 ∣ = 11 + 1

2) Simplify 11+1 to 12.

4 ∣ 2y − 3∣ = 12

3) Divide both sides by 4.

∣ 2y − 3∣ = 12 / 4

4) Simplify 12/4 to 3.

∣ 2y − 3 ∣ = 3

5) Break down the problem into these 2 equations.

2y − 3 = 3

-(2y - 3 ) - 3

6) Solve the 1st equation: 2y − 3 = 3

y = 3

7) Solve the 2nd equation: -(2y - 3 ) - 3

y = 0

8) Collect all solutions.

y = 0, 3

5 0

3 years ago

A research team conducted a study showing that approximately 15% of all businessmen who wear ties wear them so tightly that they

Helen [10]

Answer:

a) 0.913

b) 0.397

c) 0.087

Step-by-step explanation:

We are given the following information:

We treat wearing tie too tight as a success.

P(Tight tie) = 15% = 0.15

Then the number of businessmen follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

We have to evaluate:

a) at least one tie is too tight

$P(x \geq 1) = P(x = 1) +....+ P(x = 15)\\=1 - P(x = 0)\\= 1 - \binom{15}{0}(0.15)^0(1-0.15)^{15}\\=1 - 0.087\\= 0.913$

b) more than two ties are too tight

$P(x > 2) = P(x = 3) +....+ P(x = 15)\\=1 - P(x = 0) - P(x=1) - P(x=2)\\= 1 - \binom{15}{0}(0.15)^0(1-0.15)^{15}-\binom{15}{1}(0.15)^1(1-0.15)^{14}-\binom{15}{0}(0.15)^2(1-0.15)^{13}\\=1 - 0.087 - 0.231 - 0.285\\= 0.397$

c) no tie is too tight

$P(x = 0)\\=\binom{15}{0}(0.15)^0(1-0.15)^{15}\\=0.087$

d) at least 18 ties are not too tight

This probability cannot be evaluated as the number of success or the failures exceeds the number of trials given which is 15.

The probability is asked for 18 failures which cannot be evaluated.

8 0

4 years ago