Answer: 11
Step-by-step explanation: 
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
(x + 4) and (x + 1)
Step-by-step explanation:
x² + 5x + 4
Consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (+ 5)
The factors are 4 and 1 , since
4 × 1 = 4 and 4 + 1 = 5 , then
x² + 5x + 4 = (x + 4)(x + 1) ← in factored form
B is the answer I think but so t take my word for it
