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yawa3891 [41]
3 years ago
11

On Saturday Kai gave his guinea pig 80 grams of the food. The table shows the amount of each type of food he gave to the guinea

pig. Which percentage bar graph best represents the data?
Mathematics
2 answers:
DochEvi [55]3 years ago
4 0

Answer:a

Step-by-step explanation:

Alina [70]3 years ago
3 0

Answer:A

Step-by-step explanation:

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2 If a hockey team loses 33% of the games they play, what is the probability that this team will win exactly 10 games out of the
Gekata [30.6K]
  • They lose 33% of games i.e 0.33
  • They win 67% of games i e 0.67

So

  • P(A)=0.33
  • P(A')=0.67

Now

  • They win from 15games=10
  • They lose=5

The required probability

\\ \rm\rightarrowtail P(A')^{10}\times P(A)^5\times ^{15}C_{10}

\\ \rm\rightarrowtail (0.33)^{5}\times (0.67)^{10}\times \dfrac{15!}{5!10!}

\\ \rm\rightarrow 0.0039(0.0182)\times\dfrac{15(14)(13)(12)(11)10!}{5!10!}

\\ \rm\rightarrowtail 0.00007098\times \dfrac{360360}{120}

\\ \rm\rightarrowtail 0.00007098(3003)

\\ \rm\rightarrowtail 0.213

So probability

  • 0.213(100)=21.3%

Option B

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If h(x) = 5x -7,find the h(14)
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B. That is the correct answer because h(14) = 63 when you divide it by 3
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2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .
professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor \frac{2}{3} and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)

or

(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)

or

(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )

Now,  

for R = (2,1)  

the image R' = (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )

⇒ R' = (\frac{5}{3} , \frac{1}{3})  

For S = (2, -2) ,

the image S'=  (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ S' = (\frac{5}{3} , -\frac{5}{3})

and For T = (-1, -2)

The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ T' = (\frac{-1}{3} , \frac{-5}{3})

Now, label the image of RST on the graph as shown below in the attachment:

5 0
3 years ago
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