First years flies = 6,692 miles ≈7000 miles.
Second year flies = 16,429 miles ≈ 16000.
Third year flies = 24,211 miles ≈ 24000
Total number of miles flies in first and second year = 7,000miles +16,000 miles
Number of more miles he flew in the third year than the first and second year combined = Number of miles flies in third year - Total number of miles flies in first and second year
Number of more miles he flew in the third year than the first and second year combined 24,000 - (7,000+16,000)
Therefore, 24,000 - (7,000+16,000) estimation of how many more miles he flew in the third year than the first and second year combined.
Answer:
5 and 6
Step-by-step explanation:
We have to first solve the given equation 
Now, taking log in the both sides we get,
⇒ x log 10=log 432901 {Since we have the logarithm property, log aᵇ =b log a}
⇒ x =log 432901 {Since log 10=1}
⇒ x=5.636.
Therefore, the consecutive integers that are under and over the value of x are 5 and 6. (Answer)
5.7145 is bigger than the square root of 29 (which is 5.3851...)
Answer:
-2
Step-by-step explanation: has to be -2 postive it has to be but /////////////////////////////////////
Answer:
-19/10,-18/10,-17/10
Step-by-step explanation:
multiply the both numbers up and down by 10.
then find the numbers
