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3 years ago

Use the digits 1,3,4,and 7 to create two whole numbers whose product is estimated to be about 600

Mathematics

2 answers:

blagie [28]3 years ago

7 0

34 x 17 (round the 2 numbers)
30 x 20
600

Also, 34 x 17 = 578, which rounds to 600

The answer is 34 and 17

sveticcg [70]3 years ago

7 0

Answer: 34 and 17 are two numbers created from the given digits whose product is estimated to be about 600.

Step-by-step explanation:

Let 34 and 17 are two whole numbers created from the given digits.

Case 1) If we multiply 34 and 17 then 34×17=578 if we rounding up to the nearest hundreds we will get 600.

Case 2) If we rounding up the whole numbers before multiplication as

estimate of 34 to the nearest ten is 30 and 17 to the nearest ten is 20

Then the product becomes 30×20=600.

So by both the ways 34 and 17 can be used for estimated product to be 600.

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Which rule deacribes the

Marysya12 [62]

Answer:

A. ${T_{-6,-2}}\circ {r_{x-axis}}(x,y)$

Step-by-step explanation:

We have that, ΔABC is transformed to get ΔA''B''C''.

We see that the following transformations are applied:

1. Reflection across x-axis i.e. flipped across x-axis.

Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.

2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.

So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.

Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.

6 0

3 years ago

Ashad is rewriting the expression 28 a + 36 a b as a product. Which statements about the expression are accurate and relevant to

Gala2k [10]

Answer:

(B)The GCF of the numbers(28 and 36) in each term in the expression is 4.

(C)The GCF of the variables(a and ab) in each term in the expression is a.

(E)The factored form of the expression is 4a(7+9b)

Step-by-step explanation:

Given the expression: $28a+36ab$

If we write it as a product, we obtain:

$28a+36ab=4a(7+9b)$

We can see the following

The GCF of the numbers(28 and 36) in each term in the expression is 4.
The GCF of the variables(a and ab) in each term in the expression is a.
The factored form of the expression is 4a(7+9b)

The correct options are B, C, and E.

8 0

4 years ago

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

I need help 5-7 please

OlgaM077 [116]

5. 623. Just split the shape into two. then find the area of two figures that you created. Then add.
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6 0

3 years ago

A savings bank invests $58,800 in municipal bonds and earns 12% per year on the investment. How much money is earned per year?

seraphim [82]

To find the answer we simply have to find 12% of 58,800. So to do that, we can multiply it by .12

58,800 • .12 = 7,056

So $7,056 is earned per year

5 0

4 years ago

Read 2 more answers