Using pythagorean's theorem
a^2+b^2=c^2
a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
Add, divide- turn division equation into a fraction, boom
Answer:
The desired divisor is n = 21
Step-by-step explanation:
Let that number be n. Then:
-15/56 -5
---------- = ---------
n 6
Through cross-multiplication we get:
(-15/56)*6 = -5n, which reduces to:
(-15)(7) = -5n, or 3(7) = n
The desired divisor is n = 21
The scale factor is 4 and for the perimeter just use the distance formula
X^2-10x+25 = (x-5)^2 or (x-5)(x-5)