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gulaghasi [49]
3 years ago
12

In the area a square is 48 cm^2. What is the perimeter, in cm, of the square?

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
Each side of the square is 7 cm (I found the square root of 49).

Then multiply this by 4 (or add by four) to get the perimeter.

4 x 7 = 28 cm

This means the perimeter is 28 cm. Hope this helps :)
Debora [2.8K]3 years ago
3 0

144 cm

Step-by-step explanation:

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HELP ASAP!!! THANK YOU!!!
alex41 [277]

Answer:

Additional information required is

<DBA = 90°

Step-by-step explanation:

<DBA + <DBC = 180° [Linear pair]

=> <DBA = 180° - <DBC

=> <DBA = 180 - 90

=> <DBA = 90

Hence, both the angles <DBA = <DBC = 90°

As we know that when a perpendicular bisector bisects a straight line both the angles should be,

180° ÷ 2 = 90°

And above conditions also prove that

<DBA = <DBC = 90°

<em><u>Hence, DE is a perpendicular bisector of AC </u></em>

6 0
3 years ago
*ANSWER ASAP* Earth has a diameter of approximately 7926 miles. Determine the volume of Earth.
frutty [35]

Answer:

Rounding to the nearest whole number, 49 moons can fit in the earth.

Rounding to the tenth place, 50 moons can fit in the earth.

Step-by-step explanation:

To find how approximately how many moons could fit inside the earth, you would need yo find the volumes the earth and the moon.

V = 4/3 π r^3

Earth:

d = 2r

d = 7926 miles

7926 = 2r

3963 miles = r

V = 4/3 π (3963)^3

V = 4/3 π (62240377347)

V = 82987169796π cubic miles

Moon:

d = 2r

d = 2159 miles

2159 = 2r

1079.5 miles = r

V = 4/3 π (1079.5)^3

V = 4/3 π (1257963209.88)

V = 1677284279.83π cubic miles

Now you divide the volume of earth by the volume of moon to find how many moons can fit in earth

82987169796π ÷ 1677284279.83π =

approx 49

6 0
3 years ago
Given that f(x)=x^2-16x+60 and g(x)=x-10 find f(x)⋅g(x) and express the result in standard form.
storchak [24]

Answer:

x2+44x−10

Step-by-step explanation:

3 0
3 years ago
Can y’all help me plss
Troyanec [42]

<u>In a parallelogram,</u>

 ⇒the angles adjacent to each other

    ⇒ are of the same measure

        ⇒so

             ∠A = ∠C

             ∠B = ∠D

<u>Let's solve</u>:

  • ∠A = ∠C

           7z +5 = 8z - 10\\5+10=8z-7z\\8z-7z=5+10\\z = 15

  •  ∠B = ∠D

           5w-30=3w+10\\5w-3w=30+10\\2w = 40\\w=20

<u>Let's check</u>:

 ⇒ for all quadrilaterals like a parallelogram

    ⇒all the angle measures added up to 360, so:

     (7z+5)+(8z-10)+(5w-30)+(3w+10)=360\\(7(15)+5)+(8(15)-10)+(5(20)-30)+(3(20)+10)=360\\(105+5)+(120-10)+(100-30)+(60+10)=360\\110+110+70+70=360\\220+140=360\\360=360

<u>Thus</u>:

  <u>Answer: w = 20 and z = 15</u>

Hope that helps!    

7 0
2 years ago
Read 2 more answers
sketch a unit circle with angle instandard positionquestions:a. For what values of 0 is the sine increasing? Decreasing?b. For w
liq [111]

We can draw a unit circle as:

The sine is the vertical leg (or vertical projection) of the triangle formed by the angle.

The cosine will be the horizontal leg (or horizontal projection) of this same triangle.

The hypotenuse of this triangle will be the radius if the unit circle (r = 1).

a) The sine will be increasing from θ = 0° until it reaches its maximum at 90°.

Then it will be decreasing for angles between 90° and 270°.

Between 270° and 0° it will be increasing again.

b) The cosine has a maximum value for an angle of 0°.

It will decrease until 180°.

Then it will be increasing from angles between 180° and 360°.

c) We can see in the unit circle that the sine is 0 when the angle is one the horizontal axis, like when θ = 0° or θ = 180°.

The cosine will be equal to 0 when the angle is vertical: θ = 90° and θ = 270°.

Answer:

a) Increasing: (0°, 90°) and (270°, 360°)

Decreasing: (90°, 270°)

b) Increasing: (180°, 360°)

Decreasing: (0°,180°).

c) Sin(θ) = 0 for θ = 0° and θ = 180°

Cos(θ) = 0 for θ = 90° and θ = 270°

4 0
2 years ago
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