Lori bought a 25 pound bag of dog food. Every day, her dogs eat two pounds of food. How many days will the bag last? Between wha
1 answer:
a) Number of days the bag will last = 12.5 days
b) The answer lies between 12 and 13.
Step-by-step explanation:
Step 1 :
Total quantity of the dog food = 25 pounds
Total quantity of food the dog eats per day = 2 pounds
We need to find number of days the bag will last
Step 2 :
The number of days the food will last can be obtained by dividing the total quantity of food by the quantity consumed per day.
Hence
Number of days = = 12.5 days
The answer lies between 12 and 13.
Step 3:
Answer :
a) Number of days the bag will last = 12.5 days
b) The answer lies between 12 and 13.
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Answer:
(a) k=0.06217
(b)
(c) 556,755 is the population in 2012
Step-by-step explanation:
Population increased from 264,036 in 1990 to 491,675 in 2000.
Let assume , year 1990 as t=0
When t=0, population P = 264,036
When t=10, population P = 491,675
Exponential growth equation is P=P_0e^(kt)
is the initial population when t=0
So
When t=10, population P = 491,675
Plug in all the values and find out k
Divide both sides by 264036
To remove 'e' we take ln on both sides
The value of ln(e) = 1
Divide both sides by 10
k=0.06217
Exponential growth equation is
We know
Replace the value of k
Now , we find the population in 2012
For year 2012 , t= 12
So we plug on 12 for t and solve for P
P = 556755.09504
556,755 is the population in 2012
Hello,
s=48t-16t²
a)
s=0==>16t(3-t)=0==>t=0 or t=3
b)
s>32==>48t-16t²>32===>16(t²-3t+2)<0
Δ=9-8=1
==>16(t-1)(t-2)<0
==>1<t<2 (negative between the roots)
s=48t-16t²
a)
s=0==>16t(3-t)=0==>t=0 or t=3
b)
s>32==>48t-16t²>32===>16(t²-3t+2)<0
Δ=9-8=1
==>16(t-1)(t-2)<0
==>1<t<2 (negative between the roots)