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Vanyuwa [196]
3 years ago
12

Which is bigger .24 or .71

Mathematics
1 answer:
monitta3 years ago
7 0

Answer:

.71

Step-by-step explanation:

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A recipe calls for 5 deciliters of water and 236 milliliters of milk. How many milliliters of liquid does the recipe call for in
olya-2409 [2.1K]
1 deciliter is one-tenth of a liter and 1 milliliter is one-thousandth of a liter.
So: 1 liter = 10 deciliter = 100 centiliter = 1000 milliliter

This means that 1 deciliter is equal to 100 milliliters.
Based on the above:

5 deciliters = 500 milliliters
500+236 = 736

The recipe calls for 736 milliliters of liquid in total.
3 0
3 years ago
NEED HELP TO SOLVE THESE ASAP!!!!!!!!
Anika [276]
For  question 1
x^7
for question 2
h^9
5 0
3 years ago
(1-sinx+cosx)^2 = 2(1+sinx)(1+cosx)​
bogdanovich [222]

If you're trying to establish an identity, the given equation is not an identity. The proper identity would be as follows:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = (1 - sin(<em>x</em>))² + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = (1 - 2 sin(<em>x</em>) + sin²(<em>x</em>)) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 cos(<em>x</em>) - 2 sin(<em>x</em>) cos(<em>x</em>)

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) - sin(<em>x</em>) cos(<em>x</em>))

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) (1 - sin(<em>x</em>)))

… = 2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>))

But if you're trying to solve an equation:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

(1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) - (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 0

(1 + cos(<em>x</em>)) (1 - sin(<em>x</em>) - 1 - sin(<em>x</em>)) = 0

-2 sin(<em>x</em>) (1 + cos(<em>x</em>)) = 0

sin(<em>x</em>) = 0   <u>or</u>   1 + cos(<em>x</em>) = 0

sin(<em>x</em>) = 0   <u>or</u>   cos(<em>x</em>) = -1

[<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   <em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>]   <u>or</u>

… [<em>x</em> = arccos(-1) + 2<em>nπ</em>]

We have arcsin(0) = 0 and arccos(-1) = <em>π</em>, so the solution set reduces to

<em>x</em> = 2<em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>

(where <em>n</em> is any integer)

7 0
3 years ago
There are 30 students in Ms. Prema's history class. 18 of these students turned in an extra credit project at the end of the sem
kow [346]

Answer:

12 students didnt turn in a extra credit project at the end of the semester.

Step-by-step explanation:

3 0
3 years ago
Select the expressions that are equivalent to 8(6m).
Bas_tet [7]

\textsf{Hey there!}

\text{Select the expressions that are equicalent to 8(6m)}\downarrow

\text{We DON'T have any like terms so we CAN'T pair them off!}

\mathsf{8(6m) \rightarrow 8 \times 6 \times \ m}\\\mathsf{8\times 6 = 48}}\\\mathsf{48\times\  m = 48m}\\\\\\\boxed{\boxed{\mathsf{Answer: \bf{48m}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

4 0
3 years ago
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