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Anit [1.1K]
3 years ago
13

A school band gives a year-end concert. It is held in a 400-seat auditorium. Each concert ticket sells for $10, and 85% of the t

ickets are sold. How much money does the band earn from the sale of the tickets?
Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer: $3,400

Step-by-step explanation:

There are 400 seats in the auditorium which means that there are 400 tickets to be sold.

85% of these tickets are sold. The number of tickets sold is:

= 85% * 400

= 340 tickets were sold.

Each ticket sells for a total of $10.

The amount of money made from ticket sales is therefore:

= No. of tickets sold * price of ticket

= 340 * 10

= $3,400

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Number of ponits = number of games won x3 + number of games drawn Grangers have got 42 points. They have drawn 6 games. How many
Helga [31]

Answer:

Number of games Grangers won = 12

Step-by-step explanation:

Given:

Number of ponits = [Number of games won]3 + number of games drawn

Grangers have = 42 points

Number of game drawn = 6 games

Find:

Number of games Grangers won

Computation:

Number of ponits = [Number of games won]3 + number of games drawn

42 = [Number of games won][3] + 6

36 = [Number of games won][3}

[Number of games won] = 12

Number of games Grangers won = 12

7 0
3 years ago
Sea f(x)=x²+x+1
Mkey [24]

Answer:

6

Step-by-step explanation:

la respuesta es una imagen de arriba

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6 0
3 years ago
Can someone solve this please
Radda [10]
She is incorrect because x^2 can still be factored.
5 0
3 years ago
Whats the solution for y+5x=17
Travka [436]
This is my answer/how I did it :
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5x+y=17
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5 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

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This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

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And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

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And remember that this must be in absolute value, then we will have that:

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