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son4ous [18]
2 years ago
12

Ming and Carlos are selling cookie dough for a school fundraiser Customers can buy packages

Mathematics
1 answer:
jolli1 [7]2 years ago
6 0

Answer:

the cost of one package of sugar cookie dough and one package of oatmeal cookie dough is $5 and $13 respectively

Give Brainliest

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Solve the following:<br> 2x - 2 = 4x + 6
olchik [2.2K]

Answer:

x = -4

Step-by-step explanation:

<u>Step 1:  Subtract 2x from both sides</u>

2x - 2 - 2x = 4x + 6 - 2x

<em>-2 = 2x + 6</em>

<em />

<u>Step 2:  Subtract 6 from both sides</u>

-2 - 6 = 2x + 6 - 6

<em>-8 = 2x</em>

<em />

<u>Step 3:  Divide both sides by 2</u>

-8 / 2 = 2x / 2

<em>-4 = x</em>

<em />

Answer:  x = -4

5 0
3 years ago
Please help I’ll mark you as brainliest if correct
artcher [175]

Answer:

72 cm³ (see below)

Step-by-step explanation:

First, refer to the volume formula:

V = l · w · h

If you plug in all of your values and simplify, you'll get the volume:

l = 6 cm

w = 3 cm

h = 4 cm

V = (6) (3) (4)

V = 18 (4)

V = 72 cm³

Because this is volume, the measurements are units cubed, meaning it's cm³.

5 0
2 years ago
Read 2 more answers
Helen wrote and solved the equation.
Savatey [412]

Answer:

b, Helen should have added 17 to both sides of the equation

Step-by-step explanation:

just took quiz and got it right so it will help u guys too.!!!

7 0
2 years ago
Read 2 more answers
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.
aniked [119]

3 times (2x + 5) is 6x + 15.

6x + 15 = 9 + 3x.

Group by like terms. 6 = -3x

Divide to get x by itself. 6/-3 = -2

Thus -2 = x

6 0
3 years ago
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