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3 years ago

The excluded values of a rational expression are 2 and 5. Which of the following could be this expression?

Mathematics

2 answers:

SOVA2 [1]3 years ago

6 0

Answer: d on eng

Step-by-step explanation:

irina [24]3 years ago

5 0

A value will be excluded from a rational expression if it causes the denominator to be zero as dividing by zero is undefined.

An example that would work for your specific question is:

$y = \frac{(x - 3)(x-1)}{(x-2)(x-5)}$

If you plug in either 2 or 5 into this equation the denominator will be zero causing the expression to undefined there, so the values 2 and 5 are excluded from the domain of the expression.

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Help me please!

telo118 [61]

Answer:

$f^{-1}(6) = 50$

Step-by-step explanation:

Given

$f(x) = \sqrt{2x} - 4$

Required

Find $f^{-1}(6)$

First, we calculate the inverse function

$f(x) = \sqrt{2x} - 4$

Express f(x) as y

$y = \sqrt{2x} - 4$

Swap the positions of x and y

$x = \sqrt{2y} - 4$

Solve for y: Add 4 to both sides

$4 + x = \sqrt{2y} - 4+4$

$4 + x = \sqrt{2y}$

Square both sides

$(4 + x)^2 = 2y$

Divide both sides by 2

$y = \frac{(4 + x)^2}{2}$

Express y as an inverse function

$f^{-1}(x) = \frac{(4 + x)^2}{2}$

Next, solve for: $f^{-1}(6)$

Substitute 6 for x

$f^{-1}(6) = \frac{(4 + 6)^2}{2}$

$f^{-1}(6) = \frac{(10)^2}{2}$

$f^{-1}(6) = \frac{100}{2}$

$f^{-1}(6) = 50$

7 0

3 years ago

the price of a bike at store A is 5/6 the price at Store B. The price at Store A is $150.60. write and solve an equation to find

Aleks04 [339]

A = 5/6B
A = 150.60

150.60 = 5/6B
150.60 / (5/6) = B
150.60 * 6/5 = B
903.60/5 = B
180.72 = B

180.72 - 150.60 = 30.12....u save 30.12 when buying from store A

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konstantin123 [22]

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