Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
The probability that at least 1 defective card is in the sample is 
Step-by-step explanation:
Here
N = 140
and n = 20
We will use the below given formula
P(at least 1 defective) = 1 - P( 0 defectives)
P( 0 defectives) =
Total gumballs= 6 yellow+ 5 green + 4 red
= 15 gumballs
Green gumballs=5
Other gumballs= 15-5= 10
Probability= Other non-green gumballs/Total gumballs
=10/15 = 2/3
Probability of not getting green gumball is 2/3 or 66.66666.... %
The ration is 2:3.
You have to know what it is before you solve the problem
The Answer is 10x−13
Hope this helps!
