Answer:
The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Step-by-step explanation:
Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.
It is provided that .
Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:
Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
F(x) = x^4 + 81x^2
f(x) = x^2*x^2 + x^2*81
f(x) = x^2*(x^2 + 81) ... see note 1
f(x) = x^2*(x + 9i)(x - 9i) ... see note 2
note 1: if you haven't learned about complex or imaginary numbers yet, then you would stop at the line with "note 1" on it
note 2: you would stop here if you have learned about complex or imaginary numbers and you want to factor over the complex numbers. I used the rule that
a^2 + b^2 = (a+bi)*(a-bi)
Answer:
Step-by-step explanation:
.25*.1= 0.025
Answer: by multipling all 3 base sides
Step-by-step explanation: