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hodyreva [135]
3 years ago
10

An object is dropped from a height of 100 meters. The function below models the relationship between t , the number of seconds a

fter the object is dropped, and f(t) , the height of the object after it is dropped. f(t)=100−4.9t^2 Approximately how many seconds does it take for the object to hit the ground?
Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

t = 4.52

Step-by-step explanation:

Given

f(t) = 100-4.9t^2

Required

Time it hits the ground

When the object hits the ground, the height is 0.

In other words:

f(t) = 0

So, we have:

0= 100-4.9t^2

Collect like terms

4.9t^2 = 100

Divide through by 4.9

t^2 = \frac{100}{4.9}

t^2 = 20.4081632653

Take positive square roots of both sides

t = \sqrt{20.4081632653}

t = 4.51753951453

t = 4.52

<em>Hence, the ball hits the ground after 4.52 seconds</em>

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