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-BARSIC- [3]
3 years ago
7

a scientist is running a simulation of a hypothetical city since she wants to explore its environmental impact over time the cit

y's population is increasing 15 percent every year and there are currently 57,000 people what will the population be in 12 years?
Mathematics
2 answers:
lisov135 [29]3 years ago
6 0

Answer:

203,549 !!!

Step-by-step explanation:

Rus_ich [418]3 years ago
3 0
I have no clue if this is correct but the answer I got was 10,260,000
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Step-by-step explanation:

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3 years ago
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A second grade student is 4 feet tall. Her teacher is 5 2/3 feet tall. How many times as tall as the student is the teacher
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Answer:

The teacher is 1.416667 times taller than the student

Step-by-step explanation:

(5 2/3)/4

=1.416667

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3 years ago
The mean number of goals scored is 2.5.
LenaWriter [7]

Answer:

2 games.

Step-by-step explanation:

2.5 + 1.8 = 4

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3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

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3 years ago
Suppose you toss a coin 100 times and get 85 heads and 15 tails. Based on these​ results, what is the probability that the next
jenyasd209 [6]
I dont know the interger but the fraction is  17/3                                                                                                                  
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