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vichka [17]
3 years ago
13

Pick the correct value for the image of A after applying the rotation matrix.

Mathematics
2 answers:
Serggg [28]3 years ago
8 0
The answer is d, because it worked for me
artcher [175]3 years ago
7 0

Answer:

A) (- 3, -4)

Step-by-step explanation:

edge 2021

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A circle has a radius of 13 cm what is the area of the circle use 3.14 for pie
Natasha_Volkova [10]

Answer:530.66

Step-by-step explanation:

Area of circle= πr^2  

13×13=169

169×3.14=530.66

7 0
3 years ago
Find the surface area of the part of the circular paraboloid z=x^2+y^2 that lies inside the cylinder X^2+y^2=1
hichkok12 [17]

Answer:

\mathbf{\dfrac{\pi}{6}[5 \sqrt{5}-1]}

Step-by-step explanation:

Given that:

The surface area (S.A) z = x^2 +y^2

Hence the S.A is of form z = f(x,y)

Then the S.A can be represented with the equation

A(S) = \iint _D \sqrt{1+ (\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2} \ dA

where :

D = cylinder x^2 +y^2 =1

In polar co-ordinates:

D = {(r, θ): 0≤ r ≤ 1, 0 ≤ θ ≤ 2π)

Similarly, \dfrac{\partial z}{\partial x} = 2x and \dfrac{\partial z}{\partial y} = 2y

Therefore;

S.A = \iint_D \sqrt{1+4x^2+4y^2} \ dA

= \iint_D \sqrt{1+4(x^2+y^2)} \ dA

= \int^{2 \pi}_{0} \int^{1}_{0}  \sqrt{1+4r^2} \ r \ dr \d \theta

= [\theta]^{2 \pi}_{0} \dfrac{1}{8}\times \dfrac{2}{3}\begin {bmatrix} (1+4r^2)^{\dfrac{3}{2}}\end {bmatrix}^1_0

= 2 \pi \times \dfrac{1}{12}[5^{\dfrac{3}{2}} - 1]

\mathbf{=\dfrac{\pi}{6}[5 \sqrt{5}-1]}

6 0
3 years ago
GIVING BRAINLIEST!! PLS HELP :((
Vladimir79 [104]
The answer is 2 to the power of 6
3 0
3 years ago
Read 2 more answers
What is the rate of change of the line on the graph below?
Whitepunk [10]
The rate of change on the line is x line goes to the right and y line goes upward
5 0
3 years ago
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Help pls will mark brainlist !! :)
Rufina [12.5K]

Answer:

144 cubic inches

Step-by-step explanation:

a=lxwxh a=6*6*4

8 0
3 years ago
Read 2 more answers
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