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rewona [7]
1 year ago
12

Find a linear differential operator that annihilates the given function. (Use D for the differential operator.) 4 ex cos 3x

Mathematics
1 answer:
Keith_Richards [23]1 year ago
4 0

If the function is

y = 4 e^x \cos(3x)

then we have derivatives

Dy = 4 e^x \cos(3x) - 12 e^x \sin(3x)

D^2y = -32 e^x \cos(3x) - 24 e^x \sin(3x)

Now consider the linear ODE

aD^2y + bDy + cy = 0

Substituting y and its derivatives reduces the equation to

(-32a + 4b + 4c) \cos(3x) + (-24a - 12b) \sin(3x) = 0

Now,

-24a - 12b = 0 \implies b = -2a

-32a + 4b + 4c = 0 \implies c = 10a

Then the minimal ODE with the given solution is

aD^2y -2a Dy + 10ay = 0

or

\boxed{D^2y  -2 Dy + 10y = 0}

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iogann1982 [59]

Answer:

A'

Step-by-step explanation:

It is A' because they are corresponding angles, it is the same exact shape it has just been translated to a different area of the graphic plane.

If my answer is incorrect, please notify me and I'll assess what it was that I did wrong.

3 0
3 years ago
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic
Artemon [7]
<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

\sf{\rightarrow{d =  kt}}

\sf\rightarrow{20  = 2k }

\sf\rightarrow{K= \frac{20}{2} }

\sf\rightarrow{K={\color{magenta}{10}}}

<h2><u>Answer</u>:-</h2>
  • Therefore, the constant of variation is 10.
3 0
3 years ago
Find the product. Tell which strategy you used for (4 x 10) x 10
Hitman42 [59]
PEMDAS
do parentheses first
4 x 10=40
40 x 10=400
3 0
3 years ago
A rhino can run at speeds of about 28 miles per hour. What is that speed in feet per second, to the nearest whole number?
mash [69]

28 mph is approximately 41.0666... fps.

This is because 1mph is approximately 1.4666... fps.

4 0
3 years ago
Read 2 more answers
FIND THE SUM:<br> (6x^2-2x-3)+(x^2-3x+1)<br><br> 1.6x^2+6x+3<br> 2.7x^2+5x+2<br> 3.7x^2-5x-2
Butoxors [25]

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

8x^2-3-3x+1

again collect like terms

8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

5 0
2 years ago
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