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3 years ago

(11 brainly points!) What fraction is equivalent to fraction numerator negative 3 over denominator 7 end fraction?

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Answer:

Step-by-step explanation:

because 3 is negative and needs to be at the bottom,hope this help

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What is 25.4067 rounded to the nearest hundredth ?

andreev551 [17]

Answer:your answer is 25.41

Step-by-step explanation:

6 0

3 years ago

Need help with trig problem in pic

Sidana [21]

Answer:

a) $cos(\alpha)=-\frac{3}{5}\\$

b) $\sin(\beta)= \frac{\sqrt{3} }{2}$

c) $\frac{4+3\sqrt{3} }{10}\\$

d) $\alpha\approx 53.1^o$

Step-by-step explanation:

a) The problem tells us that angle $\alpha$ is in the second quadrant. We know that in that quadrant the cosine is negative.

We can use the Pythagorean identity:

$tan^2(\alpha)+1=sec^2(\alpha)\\(-\frac{4}{3})^2 +1=sec^2(\alpha)\\sec^2(\alpha)=\frac{16}{9} +1\\sec^2(\alpha)=\frac{25}{9} \\sec(\alpha) =+/- \frac{5}{3}\\cos(\alpha)=+/- \frac{3}{5}$

Where we have used that the secant of an angle is the reciprocal of the cos of the angle.

Since we know that the cosine must be negative because the angle is in the second quadrant, then we take the negative answer:

$cos(\alpha)=-\frac{3}{5}$

b) This angle is in the first quadrant (where the sine function is positive. They give us the value of the cosine of the angle, so we can use the Pythagorean identity to find the value of the sine of that angle:

$cos (\beta)=\frac{1}{2} \\\\sin^2(\beta)=1-cos^2(\beta)\\sin^2(\beta)=1-\frac{1}{4} \\\\sin^2(\beta)=\frac{3}{4} \\sin(\beta)=+/- \frac{\sqrt{3} }{2} \\sin(\beta)= \frac{\sqrt{3} }{2}$

where we took the positive value, since we know that the angle is in the first quadrant.

c) We can now find $sin(\alpha -\beta)$ by using the identity:

$sin(\alpha -\beta)=sin(\alpha)\,cos(\beta)-cos(\alpha)\,sin(\beta)\\$

Notice that we need to find $sin(\alpha)$ , which we do via the Pythagorean identity and knowing the value of the cosine found in part a) above:

$sin(\alpha)=\sqrt{1-cos^2(\alpha)} \\sin(\alpha)=\sqrt{1-\frac{9}{25} )} \\sin(\alpha)=\sqrt{\frac{16}{25} )} \\sin(\alpha)=\frac{4}{5}$

Then:

$sin(\alpha -\beta)=\frac{4}{5}\,\frac{1}{2} -(-\frac{3}{5}) \,\frac{\sqrt{3} }{2} \\sin(\alpha -\beta)=\frac{2}{5}+\frac{3\sqrt{3} }{10}=\frac{4+3\sqrt{3} }{10}$

Since $sin(\alpha)=\frac{4}{5}$

then $\alpha=arcsin(\frac{4}{5} )\approx 53.1^o$

4 0

3 years ago

Which is closest to the volume of a cylinder with a height of 11 inches and

Veseljchak [2.6K]

Answer:

The closest to the volume of cylinder is 63 in.³.

Step-by-step explanation:

Given:

Cylinder with a height of 11 inches and a circumference of 8 1/2 inches.

Now, to find the volume.

As circumference is given we get the radius by putting formula:

Circumference = 8 1/2 inches = 17/2 inches.

Let the radius be $r.$

$Circumference=2\pi r$

Taking the value of π = 3.14.

$\frac{17}{2}=2\times 3.14\times r$

$8.5=6.28\times r$

Dividing both sides by 6.28 we get:

$1.35=r$

So, radius = 1.35 inches.

Height = 11 inches.

Now, putting the formula to get the volume:

$Volume=\pi r^2h$

$Volume=3.14\times 1.35^2\times 11$

$Volume=3.14\times 1.8225\times 11$

$Volume=3.14\times 20.0475$

$Volume=62.949\ inches^3$

Hence, the volume of cylinder = 63 inches³ (approximately).

Therefore, the closest to the volume of cylinder is 63 in.³.

4 0

3 years ago

Identify the 'c' value: y = 16x2 -8% -24

iren2701 [21]

just simplify 16 x 2 - 8% - 24 and the answer would be 7.92

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3 years ago

A direct variation equation that relates x and y

jok3333 [9.3K]

Answer:

Because X and Y vary directly, the equation is the form Y =KX. We can then solve for K by using the given values for X and Y. The equation that relates X and Y is Y= 5x

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3 years ago