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podryga [215]
3 years ago
14

The radial tuberosity is the site of the attachment for the deltold muscle. True or false?

Biology
1 answer:
Fofino [41]3 years ago
6 0

Answer:(Radius is bone on right. Radial tuberosity is visible at upper left of radius.) Details. Identifiers. Latin, Tuberositas radii. TA98 · A02.4.05.007 · TA2 · 1216 · FMA · 23489 · Anatomical terms of bone. [edit on Wikidata]. Beneath the neck of the radius, on the medial side, is an eminence, the radial tuberosity; ... Ligaments that support the elbow joint also attach to the radial ...

True

Explanation:

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The answer is invasive species.


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Which animal lives in the hydrosphere and lithosphere? eagle duck shark lizard?
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6 0
3 years ago
Read 2 more answers
Although we have discussed single-slit diffraction only for a slit, a similar result holds when light bends around a straight, t
QveST [7]
<h2>Width of hair is "1.96 10⁻⁵ m"</h2>

Explanation:

  • For this diffraction problem they tell us that it is equivalent to the diffraction of a single slit, which is explained by the equation
  •      a sin θ =±  m λ
  • Where the different temrs are: “a” the width of the hair, λ the wavelength, θ the angle from the center, m the order of diffraction, which is the number of bright rings (constructive diffraction)  
  • We can see that the diffraction angle is missing, but we can find it by trigonometry, where L is the distance of the strand of hair to the observation screen and "y" is the perpendicular distance to the first minimum of intensity
  •      L = 1.25 m 100 cm/1m   = 125 cm
  •      y = 5.06 cm  
  •     Tan θ = y/L
  •     Tan θ = 5.06/12
  •      θ = tan⁻¹ ( 0.0405)
  •      θ =  2.32º
  • With this data we can continue analyzing the problem, they indicate that they measure the distance to the first dark strip, thus m = 1
  •     a = m λ / sin θ
  •     a = 1 633 10⁻⁹ 1.25/sin 2.3
  •     a = 1.96 10⁻⁵ m  
  •     a = 0.0196 mm
  • Hence, "the width of the strand of hair is   1.96 10⁻⁵ m" is correct answer

3 0
3 years ago
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