PLEASE HELP RIGHT ANSWERS ONLY!

Beverage A and Beverage B are sold in identical cans. Beverage A is 6% sugar. The portion of Beverage B that is sugar is 0.21. H

muminat

Answer:

3.5 more times sugar in B

Step-by-step explanation:

We need to see that the fact that Beverage B is 0.21 sugar can be translated to percentages, just by multiplying and dividing by 100 to get it easier to see:

0.21 * 100 /100 = 21/100 = 21% percent

This means that for every 100 units, 21 are sugar.

Now we can compare percentages directly, as both have the same volume because are sold in identical cans. We need to get how many times is 21 greater than 6. The only thing we need to do is the ratio between them:

21/6= 3.5

This implies that 21 is 3.5 greater than 6, you can verify it by multiplying 6 by 3.5 and getting 21.

So, B has 3.5 times more sugar than A.

5 0

3 years ago

2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en

Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

Given:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select k items from a group of n items without replacement. The order of the arrangement does not matter in combinations.

The combination of k items from n items is: ${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = ${n\choose k}={9\choose 3}$

$=\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84$

Thus, the number of different lab groups possible is 84.

8 0

3 years ago

Find the equation of the tangent of x^2- xy + y^2 =7 at (-1, 2)

Citrus2011 [14]

Answer:

It is 3y = 4x + 10

Step-by-step explanation:

Let's first get the slope of the curve.

[ slope is the derivative of the equation ]

${x}^{2} - xy + {y}^{2} = 7$

introduce dy/dx :

$\frac{d}{dx} ( {x}^{2} - xy + {y}^{2} ) = \frac{d}{dx} (7) \\ \\ 2x - (y + \frac{dy}{dx} ) + 2y \frac{dy}{dx} = 0$

make dy/dx the subject:

$2x - y - \frac{dy}{dx} + 2y \frac{dy}{dx} = 0 \\ \\ 2y \frac{dy}{dx} - \frac{dy}{dx} = y - 2x \\ \\ \frac{dy}{dx} (2y - 1) = y - 2x \\ \\ \frac{dy}{dx} = \frac{y - 2x}{2y - 1}$