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2 years ago

Mr quark drove his car 314 m. in 6.5 hrs. he used 12.7 gals. of gas.find these rates gallons per mi.

Mathematics

1 answer:

miskamm [114]2 years ago

8 0

Answer:

24.7 miles takes 1 gallon of gas

Step-by-step explanation:

314÷12.7=24.724409 which gets rounded to 24.7

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Today is Maria's birthday. She is 7 years old. How old is Maria in months?

Serggg [28]

Answer:

84 months

Step-by-step explanation:

Maria is 7 years old, there are 12 months in a year, multiply 12 by 7.

12 * 7 = 84

Maria is 84 months old

3 0

1 year ago

Read 2 more answers

Evaluating integral by net area

N76 [4]

The graph of $f(x)=2$ is a horizontal line. So the area under $f(x)$ on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of $g(x)=\sqrt{64-x^2}$ is the upper half of a circle with radius $\sqrt{64}=8$ . It's symmetric about $x=0$ , so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is $\frac{\pi 8^2}4=16\pi$ .

Then use the fact that the definite integral is distributive over sums, meaning

$\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi$

8 0

3 years ago

Not sure how to do this. i always struggle with proofs.

nlexa [21]

Answer:

Statement: angle QAU congruent to angle KAC

Reasoning: vert. angle congruenct thm

S: angle U congruent to angle C

R: Alt. Int. Angle Thm

S: Triangle QUA similar to Triangle KCA

R: AA Sim. Thm

Step-by-step explanation:

Practice a lot of proofs and you'll start seeing a pattern in them and it will become way easier.

5 0

3 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$