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3 years ago

Which graph has a slope of 4/5?

Mathematics

2 answers:

QveST [7]3 years ago

7 0

The second one. Hope this helps! (You should give the credit to the other person who answered because they helped me out with this.)

muminat3 years ago

6 0

The second one has a slope of 4/5

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Write a variable expression to represent the phrase.<br><br> The product of 72 and a number.

stiv31 [10]

Answer:

72+n=?

(hope this is right)

8 0

2 years ago

Evaluate A 2-B 2 for A = 3 and B = -4

r-ruslan [8.4K]

Hello there, and thank you for posting your question here on brainly.

Since we know what both of the exponents are, we can rewrite the equation for it.

3 * 2 - (-4)

We can evaluate from here.

I can see we have a positive number subtracting a negative number.

Use the rule where x - (-y) = x + y

2 * 3 + 4

Now we can get solving.

2 * 3 ==> 6

6 + 4 ==> 10

10 is the final answer.

Hope this helps! ☺♥

4 0

3 years ago

Where is the point (-1,5) located on the coordinate plane?

weqwewe [10]

The point (-1, 5) is located here:

Yes, I did draw that in paint just for you.

3 0

4 years ago

Read 2 more answers

A cake is made from the ingredients listed below.

Oksana_A [137]

To make a cake :-

Quantity of flour needed = 500 g

Quantity of butter needed = 450 g

Quantity of sugar needed = 470 g

Quantity of mixed fruit needed = 1.8 kg = 1000 g + 800 g

Quantity of eggs needed = 70 × 4 = 280 g

It's weight after adding all the ingredients =

=500 + 450 + 470 + 1000 + 800 + 280

= 3500 g

Mass that got lost while baking the cake :

$= \frac{12}{100} \: of \: 3500$

$= \frac{12}{100} \times 3500$

$=\frac{(12 \times 3500)}{100}$

$=\frac{42000}{100} \: g$

$= 420 \: g$

Final mass = Initial mass - mass that got lost

$= 3500 - 420 \: g$

$= 3080 \: g$

∴ The final mass of the cake is 3080 g .

5 0

3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

4 years ago