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Ierofanga [76]
3 years ago
11

If a rectangle has an area of 132 Units and a length of 11 units what is the width? If necessary round your answer to decimal pl

ace
Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0
<span><u><em>Answer:</em></u>
width = 12 units

<u><em>Explanation:</em></u>
<u>The area of the rectangle can be calculated as follows:</u>
area = length * width

<u>We are given that:</u>
area = 132 square units
length = 11 units

<u>Substitute with the givens in the above equation and solve for the width as follows:</u>
area = length * width
132 = 11 * width
width = </span>\frac{132}{11}<span>
width = 12 units

Hope this helps :)</span>
Rus_ich [418]3 years ago
4 0

Answer: 12.00 units

<span>An area should be measured in square units so the area in the question should be 132 square units.  In a rectangle having an area of 132 square units and a length of 11 units, the width (W) is computed as follows:</span>

W=A/L

W=132/11

<span>12.00 units</span>

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3 years ago
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
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Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

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Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
3 years ago
The length of a rectangle is one more that three times its width. If the perimeter is 42 inches, find the dimensions of the rect
Liono4ka [1.6K]
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W+3w=20
Add like terms
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Artyom0805 [142]

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Hence, domain = {all real numbers} and range = {y : y = 3}


4 0
3 years ago
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