Answer:
Third option
Step-by-step explanation:
-10x+25=0 is the correct answer. 100% sure
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Answer:
C, 33 1/3%
Step-by-step explanation:
Because there are only two even number that follow this rule: 2<x≥6, and since there are only 6 possible outcomes, the probabilty is 2/6, which is 1/3. In a percent form, this is 100%*2/3, or 33 1/3%.
34 less than (-34) the product of (multiply) 14 (14) and an unknown (x) is (=) 78 (78)
-34+14 times x=78
14 times x=14x
14x-34=78
add 34 to both sides
14x=112
divide both sdies by 14
x=8
the number is 8
The answer is going to be 5 laps per day because I did 15 laps/3days and divided each side by 3 which the answer is going to be 5/1 but it’s basically 5 since it’s going to be a whole number in this set. Therefore the unit rate of 15 laps in 3 days is going to be 5 laps per day.