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myrzilka [38]
3 years ago
5

F(x) = 3x + 2 What is f(5)?

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

17

Step-by-step explanation:

Substitute 5 in place of x

f(5) = 3*5 + 2

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Solve the following equation
Gnoma [55]
40x+8x^2=0 can be solved for x (there are two solutions):

Divide all 3 terms by the greatest common multiple (which is 8x):

40x+8x^2=0
------------- -----
       8x       8x

5 + x = 0             produces the root x = - 5.   

Setting 8x = 0 and solving for x produces the root x = 0.

Be certain to check these results.  substitute x = -5 into 40x+8x^2=0.  Is the resulting equation true or false?  Next, subs. x=-5 into 40x+8x^2=0.  Is the resulting equation true or false?
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You have 1/2 cup of yogurt. How much do you have when you triple it?
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Need help (problem and directions in the image):
Alex

Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem. The sink hole is 52.2 ft and the Perimeter of ABC is 172.2 ft

<h3>What are congruent triangles?</h3>

Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.

In the image shown:

AC = CE, BC = ED and they have the same angle (opposite angles are congruent).

Hence:

Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem.

AB = DE = 52.2 ft

Perimeter of ABC = AB + BC + AC = 50 + 70 + 52.2 = 172.2 ft

Find out more on congruent triangles at: brainly.com/question/2938476

#SPJ1

6 0
2 years ago
I need help with this, please. Any advice would be appreciated.
mote1985 [20]

Answer:

see explanation

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

where a₁ is the initial value and d the common difference

Given

S_{n} = \frac{n}{2} [ 10 + (n - 1)3 ]

Then by comparison

2a₁ = 10 ( divide both sides by 2 )

a₁ = 4 ← initial value

and d = 3 ← common difference

Thus

S_{8} = \frac{8}{2} [ 10 + (7 × 3) ]

   = 4(10 + 21)

   = 4 × 31

   = 124

8 0
4 years ago
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