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myrzilka [38]
3 years ago
5

F(x) = 3x + 2 What is f(5)?

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

17

Step-by-step explanation:

Substitute 5 in place of x

f(5) = 3*5 + 2

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natali 33 [55]

Answer:

117

Step-by-step explanation:

By adding the percentages given: 3+16+14+18+10

you get 61%

multiply 300 by .61 or 61%

you get 183

subtract 183 from 300

you are left with 117 which is the answer

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3 years ago
Robert wants to build a square sandbox that has an area of 25 feet. How long will each side be?
love history [14]
For a square all the sides and angles are the same size (number) Since the area is 25 we only have to figure out one side because every side is the same. Now we have to find out what two of the same numbers equal 25. Like the square root of 25. The answer is 5 because 5 times 5 is 25. each side will be 5ft long
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3 years ago
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J is 25 more than 3 help???
evablogger [386]
J would equal 28!!!!!!!!!!!!!!!!!!!
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4 years ago
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Hugo decided to pay $2 a week to his brother to buy a bicycle. The equation y – 10 = –2(x – 10) models the amount of money he ow
vampirchik [111]

It is $30 a week for 15 weeks

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3 years ago
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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
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