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Monica [59]
2 years ago
12

In the triangle shown below, which altitude length can be found without using the Distance Formula? What is the length?

Mathematics
2 answers:
Alika [10]2 years ago
5 0

Answer:

a

Step-by-step explanation:

The altitude from N to LM

N is vertically below LM, thus the units can be counted directly, that is 6 units

tankabanditka [31]2 years ago
5 0

Answer: a.) the altitude from N to line LM 6 units

Step-by-step explanation: Looking at the graph, you can count the units from the point N to the line, or you can find the difference between 4 and -2:  4- (-2) = 6

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Convert:<br> 2 tons 15,000 ounces = <br> ounces
amm1812
Answer 79,000
explanation 1 ton is 32,000 ounces and you have 2 so you would have 64,000 and you add the extra 15,000 to get 79,000
7 0
2 years ago
The Robotics Manufacturing Company operates an equipment repair business where emergency jobs arrive randomly at the rate of thr
cluponka [151]

Answer:

The correct answer is:

  • \lambda=0.375 \ jobs \ per \ hour
  • \mu=0.5 \ jobs \ per \ hour

Step-by-step explanation:

The given values are:

Service time varies,

Repair time = 2 hours

Standard deviation = 1.5 hours

Robotics uses per hour cost,

= $35

Company's cost per hour,

= $28

(a)

⇒ Arrival rate = Jobs per hours

then,

                       = \frac{8 \ hours}{3 \ jobs}

                       = 2.666 \ hours \ per \ job

The jobs per hour will be:

⇒  \lambda=\frac{1}{2.666}

       =0.375

(b)

⇒ Service rate = jobs per hour

then,

                      μ = \frac{1 \ repair \ job}{2 \ hours}

                         = 0.5 \ jobs

7 0
3 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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3 years ago
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M^2-m+m+3-1
Answer:
M^2+2
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Answer:

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3 years ago
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