You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.
Ummmm that’s a triangle but I guess I’ll solve for both 7x7= 49/2= 24.5 triangle. Polygon is different but I guess if the perimeter and line to the center is both 7 okay 7x5= 35x7= 245/2= 122.5 cause triangle is wxL /2 and polygon is AxP/2 soooo I hope this helped
<u>Direct Variation:</u> 

when y = 7: 
14 = 15x

<u>Inverse variation:</u> y*x = k
15 * 2 = k
30 = k
when y = 7: 7 * x = 30

Answer:
this should be the graph.
Step-by-step explanation:
I hope this helps.