Question

HELP PLSSSSSS 30 points pls no stupid things

Answer 1

Answer:

Therefore,

$(m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)=3m^{2}-mn+m$

Step-by-step explanation:

Given:

$(m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)$

Addition in Column form is as follow

     m²  +  2mn  +  n²   + 0m +  5

 + 2m² + 0mn   - 3n²  + 0m -  2

 + 0m²  -  3mn  +  2n² +  m  - 3

                                             

3m²  - mn + 0n² + m+ 0

                                             

Therefore,

$(m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)=3m^{2}-mn+m$