Answer:
(-1, -9)
Step-by-step explanation:
Recall that for 2 points (x1, y1) and (x2,y2)
the midpoints are given by
x ordinate =
y ordinate =
In our case x1 = 8, y1 = -10, x2 = -10, y2=-8
x ordinate = = [8 + (-10) ] / 2 = -1
y ordinate = = [-10 + (-8) ] / 2 = -9
hence midpoint is (-1, -9)
Explanation:
Consider the attached diagram.
Circles A and B have mutual tangents CF and DE that intersect at point F.
We know that the two tangents to a circle from an external point are congruent, so ...
FE≅ FC
FD ≅ FC
By the transitive property of congruence, both segments congruent to FC are congruent to each other:
FD ≅ FE
Therefore, CF is a bisector of DE.
