Write in point-slope form an equation for the line through

Mathematics

1 answer:

AysviL [449]2 years ago

4 0

Answer:

y=-2x+1

Step-by-step explanation:

y-y=m(x-x1)

y-(-3)=-2(x-2)

y+3=-2x+4

-3 -3

y=-2x+1

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Solve for x. Round to 3 decimal places

iVinArrow [24]

Answer:

Step-by-step explanation:

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2 years ago

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Solve the inequality for x -5x - 49 > 113

Anika [276]

X < -40.5

To find this, here are the steps:

Combine like terms like so:

-4x - 49 > 113

Then, begin to isolate the variable x by adding 49 to both sides leaving you with:

-4x > 162

Then divide by negative four. Don’t forget, dividing by negatives switches the way the sign points so your final product will be:

x < -40.5

Hope this helps!

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2 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$