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Elena-2011 [213]
3 years ago
6

Find the quotient of the quantity negative 6 times x to the 2nd power times y to the 8th power plus 12 times x times y to the 3r

d power minus 36 times x times y to the 2nd power all over 6 times x times y to the 2nd power.
Mathematics
2 answers:
olga nikolaevna [1]3 years ago
6 0
[ - 6 * x^2 * y^8 + 12*  x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =

[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =

- xy^6 + 2y - 6

Answer: - xy^6 + 2y - 6

xxTIMURxx [149]3 years ago
5 0

Answer:

The quotient is:

                    xy^6+2y-6

Step-by-step explanation:

We are asked to find the quotient of the mathematical expression which is given in terms of variable x and y is represented as:

=\dfrac{6x^2y^8+12xy^3-36xy^2}{6xy^2}

Here the numerator is:

6x^2y^8+12xy^3-36xy^2

and the denominator is:

6xy^2

We can also represent our numerator term by the method of factoring it as:

6x^2y^8+12xy^3-36xy^2=6xy^2(xy^6+2y-6)

Hence, our expression gets converted by replacing the numerator term to:

\dfrac{6x^2y^8+12xy^3-36xy^2}{6xy^2}=\dfrac{6xy^2(xy^6+2y-6)}{6xy^2}\\\\\dfrac{6x^2y^8+12xy^3-36xy^2}{6xy^2}=xy^6+2y-6

                 Hence, the quotient is:

                  xy^6+2y-6

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Hope this helps :)                                                                                                                                                          

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