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scoundrel [369]
3 years ago
5

Write the equation 8x - 5y = 20 in slope intercept form.

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

The equation in slope-intercept form is y = 8/5x-4.

I hope this helps! Have a nice day!!

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Henry divided his socks into five equal groups. Let s represent the total number of socks. Which expression and solution represe
garik1379 [7]

Answer:

option A is correct answer of this question

hope yr day will full of charm

4 0
3 years ago
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Un edificio proyecta una sombra de 7.5m.mientras que un arbol que mide 1.6 m de altura proyecta una sombra 1.85 M¿Cual es la alt
sattari [20]

Answer: The height of the building is 6.49 meters.

Step-by-step explanation:

This can be translated to:

"A building projects a 7.5 m shadow, while a tree with a height of 1.6 m projects a shadow of 1.85 m.

Which is the height of the building?"

We can conclude that the ratio between the projected shadow is and the actual height is constant for both objects, this means that if H is the height of the building, we need to have:

(height of the building)/(shadow of the building) = (height of the tree)/(shadow of the tree)

H/7.5m = 1.6m/1.85m

H = (1.6m/1.85m)*7.5m = 6.49m

The height of the building is 6.49 meters.

5 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

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Answer: 2.7 is the decimal for 2 7/10

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5/8 of the students in
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I’m thinking maybe 12 boys?
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2 years ago
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