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Citrus2011 [14]
3 years ago
9

: A coin is thrown 30 times.

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0
The relative frequency of it landing on tails is 20/30 or 2/3 or 0.667
zavuch27 [327]3 years ago
6 0

Answer:

let H represent the head's outcome

let T represents the outcome of tails.

if the coin is tossed 3times The total number outcomes are

HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

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Rename the number 600,000 in ten thousands
telo118 [61]
I think it is 60,000
4 0
3 years ago
Gunther invested $10,000 in two mutual funds. One of the funds rose 6% in one year and the other rose 9% in one year. If his inv
mote1985 [20]

Answer:

$7200 in the fund rose 6% n $2800 in the fund rose 9%

Step-by-step explanation:

let x be the amount in the fund rose 6%

gain in one year=x*6%=0.06x

total amount is 10000

so amount in the fund rose 9% = 10000-x

gain in one year=(10000-x)*9%=900-0.09x

total gain=0.06x+900-0.09x=900-0.03x

=684

900-684=0.03x

0.03x=216

x=7200

the other fund amount=10000-7200=2800


5 0
3 years ago
Read 2 more answers
6y - 5x = 5 and x= 2y + 7
jolli1 [7]
Y = -10 and x = -13 (substitute 2y + 7 for x)
5 0
3 years ago
a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect
PolarNik [594]

Number of dimes were 81 and number of quarters were 47

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

<em><u>Given that There are 128 coins in all</u></em>

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

<em><u>Also given that collection of dimes and quarters is worth $19.85</u></em>

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

d \times 0.10 + q \times 0.25 = 19.85

0.1d + 0.25q = 19.85  -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

d = 128 - q -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

<h3>q = 47</h3>

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

<h3>d = 81</h3>

Thus number of dimes were 81 and number of quarters were 47

4 0
3 years ago
Please help me I don’t know how to solve it and will mark brainiliest
Sindrei [870]

Answer: One plain roll is 4 dollars and one shiny roll is 6 dollars.

Step-by-step explanation:

lets start by saying

rolls of plain wrapping paper = x

rolls of shiny wrapping paper = y

Kathryn sold 4 plain rolls and 3 shiny rolls for 34 dollars.

4x+3y=34

Eugene sold 4 plain rolls and 2 shiny rolls for 28 dollars

4x+2y=28

Both equations will look like this.

4x+3y=34

-1(4x+2y)=(28)-1

we can multiply the second equation by -1 to get y alone. (doesn't matter which equation). Once you do that, the positive 4x and the negative 4x cancel out, 3y-2y=1y and 34-28=6. you are left with

1y=6 so one shiny roll is 6 dollars.

now use that price to find the cost of the plain roll.

lets use Kathryn's equation

4x + 3(6)=34

4x + 18= 34

      -18  -18

4x=16. Divide by 4 to find cost of one plain roll.

16÷4=4. One plain roll costs 4 dollars.

Lets check. Using Kathryn's equation,

4(4) + 3(6)=34

16+18=34

34=34. We are right.

3 0
3 years ago
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