Question

Pls Help. If you do I will give the first person who answers 100 points

Answer 1

Answer:

2%

Step-by-step explanation:

so the point $(\sqrt{3},\sqrt{7})$ is in the circumference so the distance from (0,0) to this point will be the radius of the bullseye

$x=\sqrt{(\sqrt{3}-0)^2+(\sqrt{7}-0)^2}\\\\x=\sqrt{3+7}\\\\x=\sqrt{10}$

so that's the radius

so the area will be

$A=\pi x^2\\\\A=\pi (\sqrt{10})^2\\\\A=10\pi$

so the percentage is

$P=\frac{A}{1600}\\\\=\frac{10\pi}{1600}\\\\=\frac{\pi}{160}\\\\P\approx 0.02$

so it's 2%