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DochEvi [55]
3 years ago
10

The vertex of this parabola is at (4, -3). When the x-value is 5, the

Mathematics
1 answer:
NeTakaya3 years ago
3 0
Parabola equation with a vertex at (h, k) is given by y = a(x - h)^2 + k
For the give parabola, y = a(x - 4)^2 - 3
y = a(x^2 - 8x + 16) - 3
At (5, -6)
-6 = a((5)^2 - 8(5) + 16) - 3 = a(25 - 40 + 16) - 3 = a - 3
a = -6 + 3 = -3

Therefore, the coefficient of the squared expression is -3.
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Can someone please help me with this question? Thanks.
katrin2010 [14]

Area = length x width

Area = 3x + 5 Cm x 8 cm

Multiply each term by each term.

Area = 24x + 40 square cm

3 0
3 years ago
Read 2 more answers
How do you solve this problem?
zimovet [89]

Check the picture below.

5 0
3 years ago
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Write the correct order of letters to the finish line Example ABCGH​
Usimov [2.4K]
ABCDEFGHIJKLMNOPQRSTUVWXYZ?
5 0
3 years ago
There are 23 red shirts and 16 white shirts they will be put onto shelves in piles of 8 how many shirts will not fit evenly into
Mama L [17]

Given :

There are 23 red shirts and 16 white shirts they will be put onto shelves in piles of 8.

To Find :

How many shirts will not fit evenly into 8 piles.

Solution :

We need to find the number of shirts which will not fit evenly into 8 piles.

What we need is the remainder of 23 divided by 8.

23 = 8×2 + 7

So, their are 7 shirts which will not fit evenly.

Hence, this is the required solution.

6 0
2 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
3 years ago
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