Answer:
cosx= 35. Use Trignometrical identity cosx = √1−sin2x . cos x = √1−1625 = √925 = 35 to be the ...
Missing: =0.82 | Must include: =0.82
Step-by-step explanation:
Answer:
D) Fluid ounce
Step-by-step explanation:
Fluid ounces are a <em><u>unit used to measure volume</u></em>, or <em>how much space something takes up.</em> This measurement is used for liquid ingredients, like water or milk. When a recipe calls for fluid ounces, go ahead and pull out your measuring cup; it's the most accurate way to measure this.
<h2>
I hope this helps, and stay safe!! :)</h2>
There u go tried my best to work it out!! :))
Answer:
The cutoff value for the top 5% of all IQs is 131.255.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the cutoff value for the top 5% of all IQs
This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.




The cutoff value for the top 5% of all IQs is 131.255.
Answer:
72 guests
Step-by-step explanation:
We can add up the numbers of bottles per guest, then use that total to find the number of guests from the number of bottles.
<h3>Setup</h3>
Let g represent the number of guests at the party. Then there are ...
- g/3 bottles of coke
- g/6 bottles of sprite
- g/4 bottles of lift
The total number of bottles is ...
g(1/3 +1/6 +1/4) = 54
<h3>Solution</h3>
Multiplying by the inverse of the coefficient of g, we find its value to be ...
g(4/12 +2/12 +3/12) = g(9/12) = 54
g = 54(12/9) = 72
There are 72 guests at the party.