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Kruka [31]
3 years ago
13

-6x>30 I don’t get why I’m getting it wrong

Mathematics
1 answer:
sammy [17]3 years ago
8 0
I think it might be x<-5
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Is p = 6m + 9m a proportional relationship?
Tcecarenko [31]

Answer:

yes

Step-by-step explanation:

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3 years ago
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4xy - 6xy + 5y - 9y Please also include the steps to solving it.
gizmo_the_mogwai [7]

Answer:

-2xy -4y

Step-by-step explanation:

Combine like terms:

Subtract 6xy from 4xy: 4xy-6y = -2xy

Combine Like terms:

Subtract 9y from 5y: 5y-9y= -4y

Ans: -2xy -4y

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3 years ago
Find the perimeter of the triangle.
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Https://www.geogebra.org/m/znReuq7u


Use this website to know the formula for distance: d=square root of (x2-x1)^2+(y2-y1)^2
If you can’t understand what I’m typing, Google distance formula.

The answer for your question is 9+square root of 145+square root of 82, approximately 30
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4 years ago
What is the value of the expression (7 - 2)2 ?
Irina18 [472]
(7-2)2=5*2=10
or
(7-2)2=7*2-2*2=14-4=10
5 0
4 years ago
Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

x =1 is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

8 0
4 years ago
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