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uranmaximum [27]
3 years ago
6

If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?

Mathematics
2 answers:
Dominik [7]3 years ago
7 0

Answer:

HJ=20\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The <u><em>intersecting chords theorem</em></u>  is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

so

In this problem

(RH)(HT)=(GH)(HJ)

substitute the given values

(10)(16)=(8)(HJ)

solve for HJ

HJ=160/8\\HJ=20\ units

Degger [83]3 years ago
6 0

Answer:

20 units

Step-by-step explanation:

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18 + (-8) + 11

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2 years ago
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8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

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We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

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