PLZZZ HELP
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Check the picture below.
the triangle has that base and that height, recall that A = 1/2 bh.
now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,
so, add AC + AB + CB, and that's the perimeter of the triangle.
the triangle has that base and that height, recall that A = 1/2 bh.
now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,
so, add AC + AB + CB, and that's the perimeter of the triangle.
The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5
On comparing the above equation with eqn 1, we get,
We know that product of slope of a line and slope of line perpendicular to it is -1
Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1
Thus the required equation of line is found