$length \: of \: rectangle \\ l = 5 \frac{1}{3} \: inches = \frac{16}{3} \:inches \\ \\ width \: of \: rectangle \: \\ w = \frac{2}{3} \: inch \\ \\ area \: of \: rectangle \\ = l \times w \\ \\ = \frac{16}{3} \times \frac{2}{3} \\ \\ = \frac{32}{9} \\ \\ \red{ \boxed{ \therefore area \: of \: rectangle = 3 \frac{5}{9} \: {inch}^{2} }}$

4 0

3 years ago

Traffic signs are regulated by the Manual on Uniform Traffic Control Devices (MUTCD). The perimeter of a rectangular traffic si

sasho [114]

The length and width of rectangular traffic sign are 40 and 30 inches respectively

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangular traffic sign = 140 inches

Let length and width be denoted as ‘L’ and ‘B’ respectively

Given that length is 10 inches longer than its width

L = 10 + B

<em><u>The perimeter of rectangle is given as:</u></em>

Perimeter = 2( L + B)

On substituting the values, we get

140 = 2(10 + B + B)

140 = 2(10 + 2B)

140 = 20 + 4B

B = 30

Therefore, the length is L = 10 + 30 = 40

Hence the dimensions length and width of the rectangle are 40 and 30 inches respectively.

5 0

3 years ago