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bazaltina [42]
3 years ago
11

If Yasai purchased and received 100 bags of noodles before the year end, if no payment has been made, how should this be represe

nted in the current 2019 accounting period? I.E. For the year ending 31 December 2019.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

the journal entry to record this transaction is:

Dr Merchandise inventory XY

    Cr Accounts payable XY

Since Yasai received the merchandise before the year ended, it must report this transaction by increasing both current assets (merchandise inventory) and current liabilities (accounts payable).

Under accrual accounting, transactions are recorded once they occur, and not necessarily when cash is exchanged. In this specific case, the company received an asset and it must pay for it at a later date.

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A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8
Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

8 0
3 years ago
Please help will mark brainly!
Marina86 [1]
Hey man I got u. The answer for this question is B. Peace
3 0
3 years ago
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Answer:

h ≈ 39 ft

Step-by-step explanation:

When we draw out a picture, we should see that we have to use cos∅ to solve this:

cos31.66° = x/46

46cos31.66° = x

x = 39.1542

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Step-by-step explanation:

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