Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
don't know
Step-by-step explanation:
sorry buddy
Answer: 120
Step-by-step explanation:
Because it is
Step-by-step explanation:
where are the triangles
Answer:
C
Step-by-step explanation:
We need common denominator, which in this case is 40.
6*5 is 30 and 4*8 is 32.
We add these up 62/40
Now add the wholes, 5+4 is 9
We have an improper fraction, which will add 1 to 9, causing the answer to be C.
