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storchak [24]
3 years ago
14

Simplify this expression: -2x+3 - (5 - 6x).

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

-2x+3 - (5 - 6x)

pretend that there is a -1 in front of the bracket

mutiply the bracket by -1

(-1)(5)=-5

(-1)(-6x)= 6x

-2x+3-5+6x

-2x+6x+3-5 ( combine like terms)

Answer: 4x-2

Vilka [71]3 years ago
7 0

Answer:

4x-2 for plato

Step-by-step explanation:

the guy above is correct so give him brainliest, im just supporting the fact that hes correct and i got a 100% on my plato quiz from him.

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Of the students attending a rock concert, 80 of them were 8th graders. Of these 8th graders, 25% of them were wearing ear plugs.
zhuklara [117]

Answer:

15%

Step-by-step explanation:

If 10% of the 25% of 8th graders who were male, 15% would be females because 25-10= 15. So, 15% would be my answer.

6 0
2 years ago
1/5+1/4+2/5 this is adding fractions with unlike denominators what is the answer
attashe74 [19]
What you would do is change all the fractions to 20ths so they have a common denominator. For 1/5, you multiply 4x5 to get 20 in the denominator. Whatever you multiply on the bottom, you must do at the top. Do that for all fractions and you would get this:
4/20 + 5/20 + 8/20= 17/20 because denominator stays the same, add the values in the numerator.
ANSWER: 17/20
5 0
3 years ago
What is the value of x? Help me please
Basile [38]
168 degrees
180-12=168
5 0
3 years ago
Can anybody help me out with this it’s due tomorrow please?
pogonyaev
For the first question you just need to add up all the sides. so first add all the x numbers and then add all the plain numbers.
a perimeter is the total length around the shape.
3 0
3 years ago
What is the magnitude of the position vector whose terminal point is (6, -4)?
Marysya12 [62]

Answer:

  2√13

Step-by-step explanation:

The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...

  d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)

  = √(36 +16) = √52 = √(4·13)

  d = 2√13 = |(6, -4)|

5 0
3 years ago
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