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2 years ago

Consider the equation below.

Mathematics

1 answer:

Kamila [148]2 years ago

4 0

Answer:

Option (1)

Step-by-step explanation:

$\text{log}_4(x + 3)=\text{log}_2(2 + x)$

$\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

System of equations can be written as,

$y_1=\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$y_2=\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

Therefore, system of equations given in Option (1) is the correct option.

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My digits are consecutive numbers.

Alchen [17]

Answer:

456 is the number you are looking for.

Step-by-step explanation:

Consecutive numbers are numbers which continuously follow each other in the order from smallest to largest.

Have a nice day!

6 0

2 years ago

Trigonometric Identities and Applications? help

Vadim26 [7]

$\bf h=-15cos\left( \frac{2\pi }{5}t \right)\qquad \boxed{h=8}\qquad 8=-15cos\left( \frac{2\pi }{5}t \right)
\\\\\\
\cfrac{8}{-15}=cos\left( \frac{2\pi }{5}t \right)\implies cos^{-1}\left( \frac{8}{-15}\right)=cos^{-1}\left[ cos\left( \frac{2\pi }{5}t \right) \right]
\\\\\\
cos^{-1}\left( \frac{8}{-15}\right)=\cfrac{2\pi }{5}t\implies \cfrac{5}{2\pi }\cdot cos^{-1}\left( \frac{8}{-15}\right)=t\\\\
-------------------------------$

$\bf cos^{-1}\left( \frac{8}{-15}\right)=\stackrel{radians}{\stackrel{II~quadrant}{\approx 2.13}~~,~~\stackrel{III~quadrant}{\approx 4.15}}\qquad \qquad 
t=
\begin{cases}
\frac{5}{2\pi }\cdot 2.13\\\\
\frac{5}{2\pi }\cdot 4.15
\end{cases}$

3 0

3 years ago

10+8+7(-10)-(-1)

Elina [12.6K]

Answer:

-51

Step-by-step explanation:

Let's do order of operations.

10+8-70-(-1) <- We did negative 7 times 10.

18-70-(-1) <- We did 10 plus 18.

-52-(-1) <- We did 18 minus 70

When you open the () we get:

-52--1

Negative minus a negative equals a positive.

-52+1=

-51

5 0

3 years ago

You rent an apartment that costs $1300 per month during the first year, but the rent is set to go up 7.5% per year. What would b

Serjik [45]

If I did the math right, the answer would around 3,552.89. Hopefully this was helpful.

7 0

2 years ago

A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?

DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals $2.20\times 10^{8}\,Pa$ . The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress ( $\sigma$ ), measured in pascals, in the wire with circular cross-section is: