Question

Consider the equation below.

Answer 1

Answer:

Option (1)

Step-by-step explanation:

$\text{log}_4(x + 3)=\text{log}_2(2 + x)$

$\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

System of equations can be written as,

$y_1=\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$y_2=\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

Therefore, system of equations given in Option (1) is the correct option.