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Ilya [14]
3 years ago
14

Consider the equation below.

Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

Option (1)

Step-by-step explanation:

\text{log}_4(x + 3)=\text{log}_2(2 + x)

\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}

\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}

System of equations can be written as,

y_1=\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}

y_2=\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}

Therefore, system of equations given in Option (1) is the correct option.

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7.56 hope that helps I divided 37.80/5
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Tangent Be and secant BC intersect at point B. Find the value of x. If necessary, round to the hundredths place.
djverab [1.8K]

The value of x is 15.56.

Solution:

Tangent and Secant theorem:

If one secant and one tangent are drawn to a circle from one exterior point, then the square of the length of the tangent is equal to the product of the external secant segment and the total length of the secant.

BE = 22 BD = x, CD = x

BC = x + x = 2x

By the tangent and secant theorem,

BE^2=BD \cdot BC

22^2=x \cdot 2x

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Divide by 2 on both sides of the equation, we get

242=x^2

Take square root on both side of the equation.

x = 15.56

Hence the value of x is 15.56.

8 0
3 years ago
A plumber took of his pipes and separated them into 5 equal bundles.
Ghella [55]
The correct answer is B.

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4 0
3 years ago
Please help ASAP!!!!!!!
VLD [36.1K]

Answer:

10th term is 10

Step-by-step explanation:

The nth term for finding the geometric progression is expressed as;

Tn = ar^n-1

a is the first term

r is the common ratio

n is the number of terms

a11 = ar^11-1

a11 = ar^10

Since a11 = -5 and r = -1/2

-5 = a(-1/2)^10

-5 = a(1/1024)

a= 1024 * -5

a = -5120

Nest is to get the 10th terms

a10 = ar^9

a10 = -5120 * (-1/2)^9

a10 = -5120 * -1/512

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Hence the 10th term of the sequence is 10

3 0
2 years ago
How many solutions does the following equation have?
Marysya12 [62]

Answer:

b) no solution

Step-by-step explanation:

What you always want to do in this type of problem is to combine all of your "like terms," where like terms are the part of your equation that have the same variable (or no variable). In this equation, we see three terms that have the variable "z". We can add the 12z + 15z on the left side to get 27z, and then we subtract 27z on both sides to cancel both of the 27z terms out.

Now, we are left with -6 = -5   (because we got rid of all the terms with the variable z in them). We know that -6 does not equal -5, and therefore, there is no number that we can assign to variable z such that the left side of the equation will equal the right side of the equation.

Therefore, there is no solution (because a solution to the equation would be a value that we can plug into the variable z to make the equation true).

3 0
3 years ago
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