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nekit [7.7K]
3 years ago
5

2×1,000+9×100+5×1+1×1100+3×11,000

Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer: I am not sure if this is correct but I got 2.431619300243096x10^22, 2.6746457133 x 10^13, and the the last one I also get 2.4316193 x 10^10. I AM NOT TO SURE IF I DID THIS CORRECT OR NOT, PLEASE DO NOT REPORT ME IF THIA IS WRONG, I TRIED TO HELP.

Step-by-step explanation: I AM NOT SO GOOD WITH MATH!!

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The vertex of a quadratic function is (5,-6), what is the equation of the axis of symmetry in this function?
Anestetic [448]

Answer:

x = 5

Step-by-step explanation:

A quadratic equation:

f(x) = y = a*x^2 + b*x + c

Has a vertex in a point:

(h, k) such that:

h = -b/2a

and:

k = f(-b/2a)

And the axis of symmetry (this is the line that cuts the graph in two halves) is:

x = h.

In this case, the vertex is (5, -6)

Then the axis of symmetry is:

x = 5.

7 0
3 years ago
According to Boyle's Law, if the temperature of a confined gas is held fixed, then the product of the pressure P and the volume
Bad White [126]

If <em>PV</em> = 800, then <em>P</em> can be written as a function of <em>V</em>,

<em>P(V)</em> = 800 / <em>V</em>

(a) The average rate of change of <em>P</em> as <em>V</em> increases from 200 to 250 in³ is then

(<em>P</em> (250) - <em>P</em> (200)) / (250 in³ - 200 in³) = (3.2 lb/in² - 4lb/in²) / (50 in³)

... = -0.016 (lb/in²)/in³

(Or -0.016 lb/in⁵, but I figure writing the rate as (units of pressure) per (unit volume) makes more sense.)

(b) We can also write <em>V</em> as a function of <em>P</em> :

<em>V(P)</em> = 800 / <em>P</em>

Take the derivative:

<em>V'(P)</em> = - 800 / <em>P</em>²

which immediately demonstrates that <em>V'(P)</em> ∝ 1 / <em>P</em>², as required. (The fish-looking symbol, ∝, means "is proportional to".)

If differentiating is supposed to be more involved, you can use the limit definition:

V'(P)=\displaystyle\lim_{h\to0}\frac{V(P+h)-V(P)}h

V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800}{P+h}-\frac{800}P}h

V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800P-800(P+h)}{P(P+h)}}h

V'(P)=\displaystyle800\lim_{h\to0}\frac{-\frac h{P(P+h)}}h

V'(P)=\displaystyle-800\lim_{h\to0}\frac1{P(P+h)}=-\dfrac{800}{P^2}

7 0
3 years ago
If you could give the answer without explanation it would be greatly appreciated​
zysi [14]

Answer:

i think its (4, -6)

Step-by-step explanation:

6 0
3 years ago
What is the area of a circle whose radius is 15 inches? Round your answer to the nearest tenth of a square inch. ​
boyakko [2]

Answer:

706.86 in^2

Step-by-step explanation:

The formula for the area of a circle is A = \pi r^{2}

Since your radius was given (15 in) the area is:

A=\pi (15)^{2} =225\pi =706.86 in^2

7 0
3 years ago
Given sin(theta)=-1, find sec (theta)
ElenaW [278]

First problem:

sec(theta) = 1/sin(theta) = 1/(-1) = -1

Answer: a. –1

Second problem:

cos(theta) = 1

You need to use the inverse cosine function, cos^-1 x.

theta = cos^-1(1) = 0°

Answer: c. 0°

5 0
4 years ago
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