All categories

3 years ago

I FAIpQLSep5JOTD IBL

Mathematics

1 answer:

frozen [14]3 years ago

7 0

Answer:

8 ft i think there is't much context to go off of though

Step-by-step explanation:

You might be interested in

What 1.62 divided 18564/

Vika [28.1K]

<span>The answer should be 0.00008726567

Hope this helps! </span>

8 0

3 years ago

If the scale factor is 5/3 what is the width of the new rectangle?

vlada-n [284]

Answer:

If 24 is the width then the answer is 40 and if 30 is the width then the answer is 50

Step-by-step explanation:

We multiply both sides by the scale factor to find both sides of the new rectangle. 30 * 5/3 = 50 and 24 * 5/3 = 40, so the sides of the new rectangle are 50 and 40. It matters whether 24 or 30 are the length or width, but if 24 is the width then the answer is 40 and if 30 is the width then the answer is 50

7 0

2 years ago

Write the inequality represented by the graph below

olchik [2.2K]

Answer:

y≥3x-1

Step-by-step explanation:

i did the thing

and y≥the mx+b

m=slope

b=y intercept

the symbol determines which way the shaded part faces

pls mark brainliest

5 0

2 years ago

Read 2 more answers

Diego has some money in his bank account before he starts a summer job. He deposits

Leto [7]

Answer:

he earns $7 per hour

Step-by-step explanation:

6 0

2 years ago

Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

4 0

2 years ago