The fourth choice. For example, (x+2)(x-2)>0 we'll get x>2 or x<-2 because whenever you substitute x>2 for example x = 3, the value will be higher than 0 itself.
If we substitute x = 3 (for x>2)
We'll get (3+2)(3-2)>0
5(1)>0
5>0 The statement is true.
If we substitute x = -3 (for x<-2)
We'll get (-3+2)(-3-2)>0
-1(-5)>0
5>0 The statement is true.
We don't say x>2 AND x<-2, In math, we only say x>2 OR x<-2
Answer:
segment CD is congruent to segment EB
Answer:
2
Step-by-step explanation:
![f( \frac{1}{4} ) = {16}^{ \frac{1}{4} } = \sqrt[4 ]{16} = 2](https://tex.z-dn.net/?f=f%28%20%5Cfrac%7B1%7D%7B4%7D%20%29%20%3D%20%20%7B16%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%20%5Csqrt%5B4%20%5D%7B16%7D%20%20%3D%202)
That's it, hope you enjoyed it.
Easiest method you can apply (Cramer's one). <em>"</em><em>Thanks</em><em> </em><em>me</em><em>"</em><em> </em>if i've been helpful
Answer:
41, x=-5
Step-by-step explanation:
m<DEY = m<FEY, by angle bisector theorem
(9x-4) = 41
9x = 45
x = 5
m<DEY = 41
