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Zielflug [23.3K]
2 years ago
9

HEEEEEEEELLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
Debora [2.8K]2 years ago
7 0

Answer:

6

Step-by-step explanation:

This problem centers on recognizing the relationship between fractions and repeating decimals.

<u></u>

Note the following:

\frac{1}{3}=0.33333333333333333333333333333333333333333333333...  

or more simply \frac{1}{3}=0.\bar{3}

This means that 2\frac{1}{3}=2.\bar{3}

Going back to the original expression, 3\frac{2}{3}+2.\bar{3}  simplifies to 3\frac{2}{3}+2\frac{1}{3}

Next, adding mixed numbers.  For adding mixed numbers, whole number parts and fractional parts can be added separately <em>(this is because of the associative and commutative properties of addition)... because </em>

3\frac{2}{3}+2\frac{1}{3} means the same thing as

(3+\frac{2}{3})+(2+\frac{1}{3})

Changing the order, we can write it as

3+2+\frac{2}{3}+\frac{1}{3}

Adding the whole number parts, 3+2 is 5.

Next, adding the fraction parts:

For adding fractions, one must have a common denominator (the bottom part of the fraction must be the same).  Once they are the same, the denominator just sort of "hangs out" until the end without changing, and the numerators (the tops) are added together.

Fortunately, the denominators are already the same.  So, add the numerators, and the denominator will stay as a 3.

\frac{2}{3}+\frac{1}{3}

\frac{1+2}{3}

\frac{3}{3}

It is important to recognize that any fraction* where the number on the top matches the number on the bottom, the fraction is equivalent to 1.

<em>*(except if the number we're talking about is zero)</em>

So, the fraction parts added together, are equivalent to 1, and the whole number parts added were equal to 5.  Returning to our expression...

3+2+\frac{2}{3}+\frac{1}{3}

5+\frac{3}{3}

5+1

6

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The quadratic function g(x) = ax^2 + bx + c has the complex roots (-5+9i) and (-5-9i). (you may assume that a = -1) what is the
gavmur [86]

Answer:

  • b = -10, c = -106

Step-by-step explanation:

<h3>Given</h3>

<u>Quadratic function </u>

  • g(x) = ax^2 + bx + c

with the roots:

  • (-5+9i) and (-5-9i)
<h3>To find </h3>
  • b and c if a = -1
<h3>Solution</h3>

<u>As we know the sum of the roots is -b/a and the product of the roots is c/a. Substituting values and solving for b and c:</u>

  • (-5 + 9i) + (-5 - 9i) = -b/-1
  • -10 = b
  • b = -10

And

  • (-5 + 9i)(-5 - 9i) = c/-1
  • (-5)² - (9i)² = -c
  • 25 - 81(-1) = -c
  • - c = 25 + 81
  • - c = 106
  • c = -106

g(x) = -x² -10x - 106

4 0
3 years ago
6- 6x^2- 3x = 0 solve
VARVARA [1.3K]

Answer:

The solutions are x=\frac{3)+\sqrt{153} }{-12}, x=\frac{3)-\sqrt{153} }{-12}

If you need to have them in a decimal form rounded to 3 decimals, the answers would be x=-1.281, x=0.781

Step-by-step explanation:

We are given the equation 6-6x^2-3x=0

The first thing that can be done is to rearrange the terms so that they are in descending order of power. This makes it easier to work with

This gives us -6x^2-3x+6=0

To find the solutions to this equation, we can use the quadratic formula, which will tell us that the solutions are equal to \frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

From our equation, we can gather that a=-6, b=-3, c=6

Now that we have our variables, we can plug them into the quadratic formula to get our solutions.

\frac{-(-3)+\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)+\sqrt{9+144} }{-12}\\\\\frac{3)+\sqrt{153} }{-12}

And now for our second equation

\frac{-(-3)-\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)-\sqrt{9+144} }{-12}\\\\\frac{3)-\sqrt{153} }{-12}

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Answer and Step-by-step explanation:

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\frac{C}{d} = \pi

\frac{43.96}{14} = \pi

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Wyatt is training for a race. He will run 3/4 of a mile a day for 8 days. How far will Wyatt run altogether?
AlladinOne [14]

Answer:

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