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Zielflug [23.3K]
2 years ago
9

HEEEEEEEELLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
Debora [2.8K]2 years ago
7 0

Answer:

6

Step-by-step explanation:

This problem centers on recognizing the relationship between fractions and repeating decimals.

<u></u>

Note the following:

\frac{1}{3}=0.33333333333333333333333333333333333333333333333...  

or more simply \frac{1}{3}=0.\bar{3}

This means that 2\frac{1}{3}=2.\bar{3}

Going back to the original expression, 3\frac{2}{3}+2.\bar{3}  simplifies to 3\frac{2}{3}+2\frac{1}{3}

Next, adding mixed numbers.  For adding mixed numbers, whole number parts and fractional parts can be added separately <em>(this is because of the associative and commutative properties of addition)... because </em>

3\frac{2}{3}+2\frac{1}{3} means the same thing as

(3+\frac{2}{3})+(2+\frac{1}{3})

Changing the order, we can write it as

3+2+\frac{2}{3}+\frac{1}{3}

Adding the whole number parts, 3+2 is 5.

Next, adding the fraction parts:

For adding fractions, one must have a common denominator (the bottom part of the fraction must be the same).  Once they are the same, the denominator just sort of "hangs out" until the end without changing, and the numerators (the tops) are added together.

Fortunately, the denominators are already the same.  So, add the numerators, and the denominator will stay as a 3.

\frac{2}{3}+\frac{1}{3}

\frac{1+2}{3}

\frac{3}{3}

It is important to recognize that any fraction* where the number on the top matches the number on the bottom, the fraction is equivalent to 1.

<em>*(except if the number we're talking about is zero)</em>

So, the fraction parts added together, are equivalent to 1, and the whole number parts added were equal to 5.  Returning to our expression...

3+2+\frac{2}{3}+\frac{1}{3}

5+\frac{3}{3}

5+1

6

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Answer for the question :

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is given in the attachment.

Step-by-step explanation:

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The security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 151 ft from camera 2, which was 122 f
Elena L [17]
Answer: Camera 3 covers the largest angle

---------------------------------------------------------------------------------
---------------------------------------------------------------------------------

Explanation:

Refer to the diagram shown in the attachment
Let
A = position of camera 1
B = position of camera 2
C = position of camera 3

We need to find the angle values for A, B and C

Notice how
a = distance from camera 2 to camera 3 (B to C) 
a = 122
the little 'a' is opposite the big 'A'

Also notice that
b = distance from camera 1 to camera 3 (A to C)
b = 139
the little b is opposite the big B

Also notice that 
c = distance from camera 1 to camera 2 (A to B)
c = 151
the little c is opposite the big C

So in summary so far we have
a = 122
b = 139
c = 151
we will use these values in the sections below
Make sure your calculator is in degree mode

----------------------------------

Use the law of cosines to find the measure of angle A
a^2 = b^2 + c^2 - 2*b*c*cos(A)
122^2 = 139^2 + 151^2 - 2*139*151*cos(A)
14884 = 19321 + 22801 - 41978*cos(A)
14884 = 42122 - 41978*cos(A)
14884 - 42122  = 42122-41978*cos(A)-42122
-27238  = -41978*cos(A)
-41978*cos(A) = -27238
-41978*cos(A)/(-41978) = (-27238)/(-41978)
cos(A) = 0.64886369050455
arccos(cos(A)) = arccos(0.64886369050455)
A = 49.544016303819
-----------------------------
Use law of cosines to find angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
139^2 = 122^2 + 151^2 - 2*122*151*cos(B)
19321 = 14884 + 22801 - 36844*cos(B)
19321 = 37685 - 36844*cos(B)
19321 - 37685  = 37685-36844*cos(B)-37685
-18364  = -36844*cos(B)
-36844*cos(B) = -18364
-36844*cos(B)/(-36844) = (-18364)/(-36844)
cos(B) = 0.498425795244816
arccos(cos(B)) = arccos(0.498425795244816)
B = 60.1040940123789
-----------------------------
Use law of cosines to find angle C
c^2 = a^2 + b^2 - 2*a*b*cos(C)
151^2 = 122^2 + 139^2 - 2*122*139*cos(C)
22801 = 14884 + 19321 - 33916*cos(C)
22801 = 34205 - 33916*cos(C)
22801 - 34205  = 34205-33916*cos(C)-34205
-11404  = -33916*cos(C)
-33916*cos(C) = -11404
-33916*cos(C)/(-33916) = (-11404)/(-33916)
cos(C) = 0.336242481424696
arccos(cos(C)) = arccos(0.336242481424696)
C = 70.3518896838022
-----------------------------
Or we can use a shortcut to find angle C
A+B+C = 180
C = 180-A-B
C = 180-49.544016303819-60.1040940123789
C = 70.3518896838022
-----------------------------

Summary:
angle A = 49.544016303819 degrees
angle B = 60.1040940123789 degrees
angle C = 70.3518896838022 degrees
Angle C is the largest so camera 3 sweeps out the largest angle

4 0
3 years ago
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