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Zielflug [23.3K]
2 years ago
9

HEEEEEEEELLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
Debora [2.8K]2 years ago
7 0

Answer:

6

Step-by-step explanation:

This problem centers on recognizing the relationship between fractions and repeating decimals.

<u></u>

Note the following:

\frac{1}{3}=0.33333333333333333333333333333333333333333333333...  

or more simply \frac{1}{3}=0.\bar{3}

This means that 2\frac{1}{3}=2.\bar{3}

Going back to the original expression, 3\frac{2}{3}+2.\bar{3}  simplifies to 3\frac{2}{3}+2\frac{1}{3}

Next, adding mixed numbers.  For adding mixed numbers, whole number parts and fractional parts can be added separately <em>(this is because of the associative and commutative properties of addition)... because </em>

3\frac{2}{3}+2\frac{1}{3} means the same thing as

(3+\frac{2}{3})+(2+\frac{1}{3})

Changing the order, we can write it as

3+2+\frac{2}{3}+\frac{1}{3}

Adding the whole number parts, 3+2 is 5.

Next, adding the fraction parts:

For adding fractions, one must have a common denominator (the bottom part of the fraction must be the same).  Once they are the same, the denominator just sort of "hangs out" until the end without changing, and the numerators (the tops) are added together.

Fortunately, the denominators are already the same.  So, add the numerators, and the denominator will stay as a 3.

\frac{2}{3}+\frac{1}{3}

\frac{1+2}{3}

\frac{3}{3}

It is important to recognize that any fraction* where the number on the top matches the number on the bottom, the fraction is equivalent to 1.

<em>*(except if the number we're talking about is zero)</em>

So, the fraction parts added together, are equivalent to 1, and the whole number parts added were equal to 5.  Returning to our expression...

3+2+\frac{2}{3}+\frac{1}{3}

5+\frac{3}{3}

5+1

6

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Your grades on three exams are 80, 93, and 91. What grade do you need on the next exam to have an average of 90 on the four exam
Pani-rosa [81]

<u>Answer:</u>

96

<u>Step-by-step explanation:</u>

Let's assume that the marks needed in the next exam is x. Then if the average becomes 90,

\frac{80 + 93 + 91 + x}{4}= 90

Now we can simply solve for x:

⇒ \frac{264 + x}{4}= 90

⇒ 264 + x = 360            [Multiplying both sides by 4]

⇒ x = 360 - 264            [Subtracting 264 from both sides]

⇒ x = \bf96

Therefore, you need to score 96 in your next exam to have an average of 90 on the four exams.

8 0
2 years ago
Need answer asap I’m timed!!!
Ugo [173]
Should be option 1. i cant really gv an explanation tho sry :/
3 0
4 years ago
Evaluate 7m + 3mn when m=8 and n=14
Murrr4er [49]

Answer:

392

Step-by-step explanation:

7(8) + 3(8)(14)

56 + 336

=392

*Brackets mean to multiply.

3 0
3 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{first sol'n}&11&x&11x\\&#10;\textit{second sol'n}&4&0.55&2.20\\&#10;------&-----&-------&-------\\&#10;mixture&y&0.77&0.77y&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;11+4=y\implies 15=\boxed{y}\\&#10;11x+2.2=0.77y\\&#10;----------\\&#10;11x+2.2=0.77\cdot \boxed{15}&#10;\end{cases}

solve for "x"
6 0
4 years ago
This should be the last question for the day...hopefully
andrew11 [14]
I’d think it’s equated to the one, why I think that? Idek.
5 0
3 years ago
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