Hey there!
![\left[\begin{array}{ccc}\boxed{\boxed{ \frac{6}{4}}} \end{array}\right] = \left[\begin{array}{ccc}\boxed{\boxed{150}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B%20%5Cfrac%7B6%7D%7B4%7D%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B150%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
All I did was to multiply each side by 100 which then go me this!
Hope this helps!
Answer:
5 purple beads
8 red beads
4 blue beads
Step-by-step explanation:
Find the common factor of 8 5 and 10
Which is 40
8 * 5 = 40
5 * 8 = 40
4 * 10 = 40
Answer:
(0,-1,2,5)
Step-by-step explanation:

Answer:
The answers to the first three problems are shown in the figure attached
Fourth problem answer: 3.5 cm
Step-by-step explanation:
In problem 1, move the given triangle ABC four units to the right and 2 units down as what the displacement vector "v" indicates.
You may do such by translating each vertex of the triangle ABC such number of units one at a time and then joining the vertices.
In problem 2 the requested translation vector "v" indicates 4 units to the right and 1 unit up. Do such translation for each vertex of the triangle as suggested before.
In problem 3 the requested translation "v" asks for 2 units to the left and 3 up.
Do the translation of each vertex following these instructions.
Problem 4: use a ruler and notice that the length of the vector xy given has exactly the same length as the distance between the vertices A in one triangle, and A' in the other. The same is true for the distance between vertex B and B' in the other triangle, and for the distance between C and C'.