Line segment Xy has endpoints x(5,7) and y(-3,3). Find the equation for the perpendicular bisector of line segment xy
1 answer:
Answer: The equation for the perpendicular bisector of line segment xy is .
Explanation:
It is given that the line segment xy has endpoints x(5,7) and y(-3,3).
The bisector divides the line segment xy in two equal parts, so the bisector must be passing through the midpoint of xy.
Midpoint of two points (x_1,y_1) and (x_2,y_2) is calculated as,
Midpoint of xy is,
So, the perpendicular bisector must be passing through the point (1,5).
The slope of line passing through the point (x_1,y_1) and (x_2,y_2) is calculated as,
Slope of line segment is . Therefore the slope of perpendicular bisector is -2 because the the product of slopes of two perpendicular lines is always -1.
The line passing through the point (x_1,y_1) with slope m is defined as,
Bisector passing through the point (1,5) with slope 2.
Therefore, the equation for the perpendicular bisector of line segment xy is .
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a.
A secant line is a line which intersects the circle at 2 different points.
A tangent line is a line which has only one point in common with the circle.
Check picture 1: The orange line s is a secant line, the blue line t is a tangent line.
b.
An inscribed angle is an angle formed by using 3 points of a circle.
The main property of an inscribed angle is that its measure is half of the measure of the arc it intercepts.
Check picture 2: If
A central angle is an angle whose vertex is the center of the circle, and the 2 endpoints of the rays are points of the circle.
The main property is: the measure of the central angle is equal to the measure of the arc it intercepts.
Check picture 2
2.
To construct the inscribed circle of a triangle, we first draw the 3 interior angle bisectors of the triangle.
They meet at a common point called the incenter, which is the center of the inscribed circle.
We open the compass, from the incenter, so that it touches one of the sides at only one point. We then draw the circle. (picture 3)
To draw the circumscribed circle, we first find the midpoints of each side. We then draw perpendicular segments through these (the midpoints.) They meet at one common point, which is the circumcenter: the center of the circumscribed circle.
We open the compass from the circumcenter to one of the vertices of the triangle. We draw the circle, and see that it circumscribes the triangle.
(picture 4)
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Given an equation of a circle:
To determine the center and the radius of the equation we must write the above equation in the form :
Then, (a, b) is the center, and r is the radius of this circle. We do this process by completing the square.
Note that
Thus we have:
Thus, the center is (1, -3), and the radius is 2.
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and the circumference is given by the formula C=2πr.
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So the perimeter of one slice is 65.5+65.5+2.62π=131+2.62π