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Readme [11.4K]
3 years ago
14

HELP I NEED HELP ASAP

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

The answer is Door you can choose C because is likely to be the answer

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What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?
nata0808 [166]

Answer:

y=2x+7

Step-by-step explanation:

<u><em>The correct question is</em></u>

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

so

the opposite reciprocal is m=2

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=2\\point\ (-2,3)

substitute

y-3=2(x+2)

<em>Convert to slope intercept form</em>

y=mx+b

isolate the variable y

y-3=2x+4

y=2x+4+3

y=2x+7

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3 years ago
What are the best ways
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Answer:?????????

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Expanded form for 67.943
ratelena [41]
67.943

= 60.000 + 7.000 + 0.900 + 0.040 + 0.003
6 0
3 years ago
Triangle ABC was transformed to be triangle FED using
vampirchik [111]

Answer:

the triangle was rotated about 90 degrees i think

4 0
2 years ago
Please help quick for 25 points with explanations. Any silly and absurd answers will be reported.
amid [387]

Answer:

Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±\sqrt{61})/2. So, PQ=\frac{\sqrt{61} }{2}, PQ²=\frac{61}{4}. Thus, the answer is 61+4=65.

Step-by-step explanation:

4 0
3 years ago
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